Trang chủBilliardsAaron Hill beats Antoni Kowalski 4-2 with three centuries to seal Scottish Open spot
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Aaron Hill beats Antoni Kowalski 4-2 with three centuries to seal Scottish Open spot
Core answer: Aaron Hill giành vé dự Scottish Open tháng 12 sau khi thắng Antoni Kowalski 4-2 tại vòng loại, với ba cú century gồm 139, 121 và 100. Key facts: - Hill thắng 4-2, lần thứ hai trong năm ngày đánh bại Kowalski. - Ba cú century: 139, 121 và 100. - Hill đạt hạng 37 thế giới tạm thời, cao nhất sự nghiệp. - Trận kế tiếp gặp Thepchaiya Un-Nooh tại Northern Ireland Open. - Jordan Brown gặp Steven Wardropper cùng ngày để giành suất tới Edinburgh. Source: World Snooker Tour, báo cáo vòng loại mùa giải 2025/26. Related Q&A: Hỏi: Aaron Hill đã ghi bao nhiêu cú century trong trận thắng Kowalski? Đáp: Ba cú century, gồm 139, 121 và 100. Hỏi: Đối thủ kế tiếp của Aaron Hill là ai? Đáp: Thepchaiya Un-Nooh tại vòng một Northern Ireland Open ở Belfast. Hỏi: Jordan Brown gặp ai để giành vé dự Scottish Open? Đáp: Steven Wardropper của Scotland trong trận vòng loại diễn ra cùng ngày.
Aaron Hill came from behind twice and produced three centuries—139, 121 and 100—to beat Antoni Kowalski 4-2 in the Scottish Open qualifying round on Sunday morning. The 24-year-old Irishman has now qualified for the Northern Ireland Open, the International Championship and the Scottish Open in a single week, underlining his solid start to the new campaign. His 139 came through a total clearance, before a 121 levelled the match at 2-2. A break of 56 moved him ahead, and a 100 sealed the win. This result lifts Hill to a career-high 37th in the provisional world rankings. Next, he faces Thepchaiya Un-Nooh in the first round of the Northern Ireland Open in Belfast. Later on the same day, Jordan Brown takes on Scotland's Steven Wardropper for a chance to play at the Meadowbank Sports Centre in Edinburgh.
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